A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A. The magnitude of the magnetic field at the center of the coil is (Take, permeability of free space as 4 10^-7 SI units) [NEET…

Question

A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A. The magnitude of the magnetic field at the center of the coil is (Take, permeability of free space as 4 10^-7 SI units) [NEET 2024]

Accepted Answer

Correct answer: C. (c) Given, number of turns N=100 radius, r=10 cm=10 10^-2 m current, I=7 A Magnetic field at the center of a solenoid, B= _0 NI2r = 4 10^-7 100 72 10 10^-2 =44 10^-4 =4.4 10^-3 T =4.4 mT

$A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A. The magnitude of the magnetic field at the center of the coil is (Take, permeability of free space as 4 π \times 10^{- 7} SI units) [NEET 2024]$

Solution

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