A voltmeter of 250 mV range having a resistance of 10 is converted into an ammeter of 250 mA range. The value of necessary shunt is (nearly)

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Correct answer: C. (c) We have ,V_g=GI_g ⇒250 10^-3=10 I_g ⇒I_g=25 10^-3A . Let the shunt required to convert this voltmeter into ammeter be R_s. Then, (I-I_g)R_s=I_gR_g ⇒R_s= I_gR_gI-I_g - 10 (25 10^-3)250 10^-3-25 10^-3- 109 ≈1 .

$A voltmeter of 250 mV range having a resistance of 10Ω is converted into an ammeter of 250 mA range. The value of necessary shunt is (nearly)$

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