A circular loop of radius r is carrying current I A. The ratio of magnetic field at the center of circular loop and at a distance r from the center of the loop on its axis is:

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Accepted Answer

Correct answer: C. (c) Magnetic field due to current carrying circular loop on its axis is given as _0ir^22(r^2+x^2)^3/2 At center, x = 0, B_1= _0i2r At x = r, B_2 = _0i2 2 2r B_1B_2=2 2

$A circular loop of radius r is carrying current I A. The ratio of magnetic field at the center of circular loop and at a distance r from the center of the loop on its axis is:$

Solution

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