A charged particle carrying charge 1 μC is moving with velocity (2i+3j+4k )ms^-1. If an external magnetic field of (5i+3j-6k ) 10^-3 T exists in the region where the particle is moving, then the forc…

Question

A charged particle carrying charge 1 μC is moving with velocity (2i+3j+4k )ms^-1. If an external magnetic field of (5i+3j-6k ) 10^-3 T exists in the region where the particle is moving, then the force on the particle is F 10^-9 N. The vector F is

Accepted Answer

Correct answer: B. (b) Given: q=1 μC ;v=2i+3j+ 4k ms B=(5i+3j-6k) 10^-3 T ;F_M=F 10^-9 N Magnetic force, F_M=q (v B ) v B=(ijk23453-6) 10^-3 = [i (-18-12 )-j (-12-20 )+k (6-15 ) ] 10^-3 = (-30j+32j-9k ) 10^-3 ∴ F_M=1 10^-6 10^-3(-30i+32j-9k) F_M=(-30i+32j-9k) 10^-9 N So, F=-30i+32j-9k

$A charged particle carrying charge 1 μC is moving with velocity (2 i + 3 j + 4 k) m s^{- 1} . If an external magnetic field of (5 i + 3 j - 6 k) \times 10^{- 3} T exists in the region where the particle is moving, then the force on the particle is F \times 10^{- 9} N . The vector F is$

Solution

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