The magnetic field at the center of a current carrying loop of radius 0.1 m is 5 5 times that at a point along its axis. The distance of this point from the center of the loop is

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Correct answer: A. (a) Let us consider a point P at a distance x from the centre of loop, where magnetic field is given by B_0=5 5B. ( B_0 is the magnetic field at center). If current I is flowing through loop and radius of loop is R, then B= _0IR^22(x^2+R^2)^ 32 According to question, 5 5 _0IR^22(x^2+R^2)^ 32= _0I2R ⇒ ( 5R )^3=(x^2+R^2)^ 32 ⇒5R^2=(x^2+R^2) or x^2=4R^2 or x= 2R Here, R=0.1 m ⇒x=0.2 m

$The magnetic field at the center of a current carrying loop of radius 0.1 m is 55 times that at a point along its axis. The distance of this point from the center of the loop is$

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