A bullet of mass 20 g moving with 500 ms^-1 is pierced 1 cm into a wooden block, then the retarding force experienced by the bullet is

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Accepted Answer

Correct answer: D. (d) Mass, m=20 g=20 10^-3 kg velocity, u=500 m/s distance, d=1 cm=0.0/m final velocity, v=0 Using Equation of Motion, v^2-u^2=2 ad - (500 )^2=2 a 0.01a=- 500 500002 0.01=-1.25 10^7 m/s^2 using newton's second law, F= maF=20 10^-3 1.25 10^7 F=250 10^3 N

$A bullet of mass 20 g moving with 500 ms^{- 1} is pierced 1 cm into a wooden block, then the retarding force experienced by the bullet is$

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