In a lift moving up with an acceleration of 5 m s^-2, a ball is dropped from a height of 1.25 m. The time taken by the ball to reach the floor of the lift is ...... (nearly) (g=10 m s^-2) )

Question

Accepted Answer

Correct answer: D. (d) Time taken by the ball to reach the floor of the lift is t= 2ha+g Here, h=1.25 m ,g=10 m s^-2 ,a=5 m s^-2 ∴t= 2 1.25 m (5+10 )ms^-2=0.4 s

$In a lift moving up with an acceleration of 5 m s^{- 2}, a ball is dropped from a height of 1.25 m . The time taken by the ball to reach the floor of the lift is ...... (nearly) (g = 10 m s^{- 2}))$

Solution

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