A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2 :1. What will be the ratio of their nuclear size (nuclear radius)?

Question

Accepted Answer

Correct answer: D. (d) Velocity ratio ( _1 : _2 )=2 :1. Mass ( m ) ∝ Volume ∝r^3 . According to law of conservation of momentum, m_1v_1=m_2v_2 Therefore v_1 _2= m_2m_1= r_2^3r_1^3 or r_1r_2= ( v_2 _1 )^1/3= ( 12 )^1/3= 12^1/3 or r_1 :r_2=1 :2^1/3 .

$A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2 : 1 . What will be the ratio of their nuclear size (nuclear radius)?$

Solution

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