The rate of radioactive disintegration at an instant for a radioactive sample of half life 2.2 10^9s is 10^10s^-1. The number of radioactive atoms in the sample at that instant is,

Question

Accepted Answer

Correct answer: D. (d) Given, t_1/2=2.2 10^9s and rate of radioactive disintegration, dN dt=10^10s^-1 = 0.693t_1/2= 0.6932.2 10^9=3.15 10^-10s^-1 Now, we know that, N=N_0e^- λt ⇒ dN dt=- N_0e^- λt=- λN ⇒10^10=3.15 10^-10 N ⇒N=3.17 10^19

$The rate of radioactive disintegration at an instant for a radioactive sample of half life 2.2 \times 1 0^{9} s is 1 0^{10} s^{- 1} . The number of radioactive atoms in the sample at that instant is,$

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