The binding energy of deuteron is 2.2 MeV and that of _2^4 He is 28 MeV .If two deuterons are fused to form one _2^4 He then the energy released is

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Accepted Answer

Correct answer: C. (c) _1^2H+ _1^2H _2^4 He+ energy Energy released =B .E . of _2^4 He-2 (B .E . of _1^2H ) =28-2(2 2)=28-4 4 =23 6 MeV

$The binding energy of deuteron is 2.2 MeV and that of_{2}^{4} He is 28 MeV .If two deuterons are fused to form one_{2}^{4} He then the energy released is$