In a radioactive decay, an element _zX^A emits four -particles, three -particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are

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Accepted Answer

Correct answer: C. (c) Emission of -particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of -particle increases the atomic number by 1 while the mass number remains unchanged. Emission of -particle both the atomic number and the mass number remain unchanged. ∴ After the emission of four -particles, three -particles and eight photons, Decrease in atomic number =4 2-3 1=5 Decrease in mass number =4 4-0=16 Thus, the atomic number and mass number of resulting final nucleus are Z-5 and A-16 respectively. ∴ The resulting final nucleus is _Z-5Y^A-16.

$In a radioactive decay, an element_{z} X^{A} emits four α -particles, three β -particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are$

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