Two rotating bodies A and B of masses m and 2m with moments of inertia I_A and I_B (I_BI_A ) have equal kinetic energy of rotation. IfL_A and L_B be their angular momenta respectively, then

Question

Two rotating bodies A and B of masses m and 2m with moments of inertia I_A and I_B (I_B>I_A ) have equal kinetic energy of rotation. IfL_A and L_B be their angular momenta respectively, then

Accepted Answer

Correct answer: C. (c): Here, m_A=m ,m_B=2m Both bodies A and B have equal kinetic energy of rotation k_A=k_B ⇒ 12I_A _A^2= 12I_B _B^2 ⇒ ^2A _B^2= I_BI_A (i) Ratio of angular momenta, L_AL_B= I_A _AI_B _B= I_AI_B I_BI_A [Using eqn . (i) ] = I_AI_B<1( I_B>I_A ) L_B>L_A

$Two rotating bodies A and B of masses m and 2 m with moments of inertia I_{A} and I_{B} (I_{B} > I_{A}) have equal kinetic energy of rotation. If L_{A} and L_{B} be their angular momenta respectively, then$

Solution

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