A solid sphere of 100 kg and radius 10m moving in a space becomes a circular disc of radius 20m in one hour. Then the rate of change of moment of inertia in the process is

Question

Accepted Answer

Correct answer: A. (a) Given, mass of solid sphere or disc M=100 kg Radius of solid sphere, R=10m Radius of circular disc, r=20m and time =1 hour =60 minute =60 60 sec Moment of inertia of the solid sphere, I_s= 25MR^2= 25 100 (10 )^2=4000 kg-m^2 Similarly, Moment of inertia of the disc, I_c= 12Mr^2= 12 100 (20 )^2=20 ,000 kg-m^2 Rate of change of moment of inertia = I_c-I_st= 20000-400060 60= 1600060 60= 16036= 409 kg-m^2s^-1

$A solid sphere of 100 kg and radius 10 m moving in a space becomes a circular disc of radius 20 m in one hour. Then the rate of change of moment of inertia in the process is$

Solution

More Rotational Mechanics PYQs