The pair of quantities having same dimensions is

Question

Accepted Answer

Correct answer: C. (c) Impulse =Force time = [ MLT^-2 ] [T ]= [ MLT^-1 ] Surface tension = Force1 ength= [ MLT^-2 ] [L ]= [ML^0T^-2 ] Angular momentum =Moment of inertia angular velocity = [ML^2 ] [T^-1 ]= [ML^2T^-1 ] Work =Force distance = [ MLT^-2 ] [L ]= [ML^2T^-2 ] Energy = [ML^2T^-2 ] Torque = Force distance = [ MLT^-2 ] [L ]= [ML^2T^-2 ] Young’s modulus = Force/ Area Changein length/ originallength = [ MLT^-2 ]/ [L^2 ] [L ]/ [L ]= [ML^-1T^-2 ] Hence, among the given pair of physical quantities work and torque have the same dimensions [ML^2T^-2 ] .

$The pair of quantities having same dimensions is$

Solution

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