10 divisions on the main scale of a Vernier calliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is :

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Correct answer: D. (d) 10 MSD=11 VSD 1 VSD= 1011 MSD LC=1 MSD-1 VSD =1 MSD- 1011 MSD = 1 MSD11 = 511 units

$10 divisions on the main scale of a Vernier calliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is :$

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