Reaction of [Co(H_2O)_6]^2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t_2g-orbitals of the product is_______.

Question

Accepted Answer

Correct answer: 6. (6) [Co(H_20)_6]^2+ +NH_3(excess)→ [Co(NH_3)_6]^3+ + 6H_2O Diamagnetic ↓ Low spin complex Co^3+⇒3d^64s° ⇒t_2g^6 e_g^0 Total number electrons = 6

$Reaction of [Co(H_{2} O)_{6}]^{2 +} with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t_{2 g} -orbitals of the product is_______.$

Solution

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