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JEE · NEET Previous Year Question

$Select the option with correct property -$

Topic: JEE PYQ

Answer: D. Full step-by-step solution below.

A $(Ni (CO)_{4}) and (NiCl_{4})^{2 -} both diamagnetic$
B $(Ni (CO)_{4}) and (NiCl_{4})^{2 -} both paramagnetic$
C $(NiCl_{4})^{2 -} diamagnetic, (Ni (CO)_{4}) paramagnetic$
D $(Ni (CO)_{4}) diamagnetic, (NiCl_{4})^{2 -} paramagnetic$

Correct answer: D

Solution

(d) (Ni (CO)_{4}) \to diamagnetic, sp^{3} hybridisation, number of unpaired electrons = 0 (NiCl_{4})^{2 -}, \to paramagnetic, sp^{3} hybridisation, number of unpaired electrons = 2

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