CrCl_3 xNH_3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558^ C. Assuming 100 \% ionisation of this complex and coordination number of…

Question

CrCl_3 xNH_3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558^ C. Assuming 100 \% ionisation of this complex and coordination number of Cr is 6 , the complex will be (Given K_f=1.86 K kg mol^-1 )

Accepted Answer

Correct answer: A. (a) T_f=iK_fm 0.558=i 1.86 0.1 i= 0.5580.186=3Number of ions when 100 ∖ \% ionisation takes place =3 ( Cr ( NH_3 )_5 Cl ) Cl_2 aqueous solution ( Cr ( NH_3 )_5 Cl^2+ )^2++2 Cl^-Number of ions =3

$CrCl_{3} \cdot xNH_{3} can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558^{\circ} C . Assuming 100 % ionisation of this complex and coordination number of Cr is 6 , the complex will be (Given K_{f} = 1.86 K kg mol^{- 1})$

Solution

More Coordination Compounds PYQs