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JEE Previous Year Question

$Dichromate ion is treated with base, the oxidation number of Cr in the product formed is:$

Topic: JEE PYQ

Answer: 6. Full step-by-step solution below.

Correct answer: 6

Solution

6 C r_{2} O_{7}^{2 -} + 2 O H^{-} = 2 Cr O_{4}^{2 -} + H_{2} O 2 C r_{2} O_{7}^{2 -} x + (- 2 \times 4) = - 2 x = 6

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