X is the number of geometrical isomers exhibited by $(Pt (NH_{3}) (H_{2} O) BrCl)$ .
Y is the number of optically inactive isomer(s) exhibited by $(CrCl_{2} (ox)_{2})^{3 -}$
Z is the number of geometrical isomers exhibited by $(Co (NH_{3})_{3} (NO_{2})_{3})$ .
The value of $X + Y + Z$ is .

Question

X is the number of geometrical isomers exhibited by

(Pt (NH_{3}) (H_{2} O) BrCl)

.
Y is the number of optically inactive isomer(s) exhibited by

(CrCl_{2} (ox)_{2})^{3 -}

Z is the number of geometrical isomers exhibited by

(Co (NH_{3})_{3} (NO_{2})_{3})

.
The value of

X + Y + Z

is .

Accepted Answer

Correct answer: 6. (6) For ( Pt ( NH_3 ) (H_2O ) BrCl ) with square planar geometry and four different ligands, geometrical isomerism arises from different positional arrangements: X=3. For ( CrCl_2 ( ox )_2 )^3-, the trans isomer is optically inactive (meso compound) while cis is optically active, giving Y =1. For ( Co ( NH_3 )_3 ( NO_2 )_3 ) in octahedral geometry, facial (fac) and meridional (mer) isomers are possible: Z=2. Therefore, X+Y+Z=3+1+2=6

$X is the number of geometrical isomers exhibited by (Pt (NH_{3}) (H_{2} O) BrCl) . Y is the number of optically inactive isomer(s) exhibited by (CrCl_{2} (ox)_{2})^{3 -} Z is the number of geometrical isomers exhibited by (Co (NH_{3})_{3} (NO_{2})_{3}) . The value of X + Y + Z is .$

Solution

More Coordination Compounds PYQs