In basic medium CrO_4^2-oxidizes S_2O_3^2-to form SO_4^-2 and itself changes into Cr ( OH )_4^-. The volume of 0.154 M CrO_4^2-required to react with 40 mL of 0.25 MS_2O_3^2-is ____ml (Rounded-off to…

Question

In basic medium CrO_4^2-oxidizes S_2O_3^2-to form SO_4^-2 and itself changes into Cr ( OH )_4^-. The volume of 0.154 M CrO_4^2-required to react with 40 mL of 0.25 MS_2O_3^2-is ____ml (Rounded-off to the nearest integer)

Accepted Answer

Correct answer: 173. (173) 17H_2O+8 CrO_4+3 S_2O_3 6 SO_4+8 Cr ( OH )_4^-+2 OH^- Volume of 0.154M CrO_4 ^2- can be calculated by applying mole-mole analysis According to mole-mole analysis, 0.154 V/8=40 0.25/3 V=173 mL So, In the basic medium CrO_4 ^2- oxidizes S_2O_3^2- to form SO_4 ^-2 and itself changes into Cr ( OH )_4^-. The volume of 0.154M CrO_4 ^2- required to react with 40 mL of 0.25 MS_2O_3^2- is 173 mL.

$In basic medium CrO_{4}^{2 -} oxidizes S_{2} O_{3}^{2 -} to form SO_{4}^{- 2} and itself changes into Cr (OH)_{4}^{-} . The volume of 0.154 M CrO_{4}^{2 -} required to react with 40 mL of 0.25 M S_{2} O_{3}^{2 -} is ____ml (Rounded-off to the nearest integer)$

Solution

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