An element, X has the following isotopic composition: 2 0 0 X: 90% 1 9 9 X: 8.0% 2 0 2 X: 2.0% The weighted average atomic mass of the naturally occurring element X is closest to

Question

Accepted Answer

Correct answer: D. (d) Average isotopic mass ofX 2 0 0×9 0+1 9 9×8+2 0 2×2 90+8+2 = 1 8 0 0 0+1 5 9 2+4 0 41 0 0=1 9 9.9 6 a.m.u. ≈2 0 0 a.m.u.

$An element, X has the following isotopic composition: 200 X : 90% 199 X : 8.0% 202 X : 2.0% The weighted average atomic mass of the naturally occurring element X is closest to$

Solution

More Some Basic Concepts of Chemistry PYQs