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JEE · NEET Previous Year Question

$10 cm^{3} of 0.1 N monobasic acid requires 15 cm^{3} of sodium hydroxide solution whose normality is$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $0.066 N$
B $0.66 N$
C $1.5 N$
D $0.15 N$

Correct answer: A

Solution

(a) : From normality equation N_{1} V_{1} = N_{2} V_{2} \Rightarrow N_{a} V_{a} = N_{b} V_{b} N_{b} = \frac{0.1 \times 10}{15} = 0.066 N

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