20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final
concentration of the solution is $\times 10^{- 2} M$ . (Nearest integer)

Question

20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is 10^-2M. (Nearest integer)

Accepted Answer

Correct answer: 57. (57) M_F= M_1V_1+M_2V_2V_1+V_2 = 2 20+0.5 400420=0.571M =57.1 10^-2M =57

$20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is \times 10^{- 2} M . (Nearest integer)$