The mole fraction of a solute in a 100 molal aqueous solution___ 10^-2 (Round off to the Nearest Integer) [Given: Atomic masses: H: 1.0u ,O :16.0u ].

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Accepted Answer

Correct answer: 64. (64) Further 100 molal aqueous solution is given which means 100 moles of solute is dissolved in 1 Kg. of the solvent. From here we can get The number of moles of the solute =100 Weight of the solvent =1 kg. Number of moles of the solvent = Weight of the solvent Molecular weight of the solvent = 100018 Now, apply the formula of the mole fraction written above Mole raction = Moles of solute Total moles = 100(100+ 100018) = 100 1800+100018 = 100 280018 = 18002800 =0.64 =64 10^-2 The mole fraction of a solute in a100 molal aqueous solution is 64 10^-2.

$The mole fraction of a solute in a molal aqueous solution___ (Round off to the Nearest Integer) [Given: Atomic masses: H: .$

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