0.75 mole of solid X_4 and 2 mole of O_2 are heated to completely react in a closed rigid container to form only one gaseous compound (no reactant left behind). Find the ratio of final pressure at 32…

Question

0.75 mole of solid X_4 and 2 mole of O_2 are heated to completely react in a closed rigid container to form only one gaseous compound (no reactant left behind). Find the ratio of final pressure at 327ºC to the initial pressure at 27ºC in the flask. Fill your answer as x, where ratio is x : 1.

Accepted Answer

Correct answer: 1. (1 ) Mole atoms of X = 0.75 × 4 = 3 Mole atoms of O = 2 × 2 = 4 Hence the product is X_3O_4 (g) Initial moles of gaseous reactants, n_1 = 2 (oxygen only) Final moles of gaseous product, n_2 = 1 (X_3O_4) Hence, P_2P_1 = n_2T_2n_1T_1 = 1×6 0 02×3 0 0 = 1 or P_2 : P_1 : 1 : 1

Solution

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