cos^n-1 ⁡x sin^n+1 ⁡x dx ,n 0 is

Question

Accepted Answer

Correct answer: C. (c) : Given integral can be written as cot^n-1 ⁡x sin^2 ⁡x dx= cot^n-1 ⁡x cosec^2 ⁡ xdx Put cot ⁡x=t ⇒ - cosec^2 ⁡ xdx= dt ∴ - t^n-1 dt= -t^nn+C= - cot^n ⁡xn+C

$\int \frac{cos ^{n - 1} x}{sin ^{n + 1} x} dx, n \neq = 0 is$

Solution

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