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JEE Previous Year Question

∫3−log9​⁡x2dx=

Topic: JEE PYQ

Answer: B. Full step-by-step solution below.

  1. A2log⁡|x|+C
  2. Blog⁡|x|+C
  3. C−log⁡|x|+C
  4. D−2log⁡|x|+C

Correct answer: B

Solution

(b)
  ∫3−log9​⁡x2dx=∫3log9​⁡(x21​)dx=∫(x21​)log9​⁡3dx=∫(x21​)21​dx=∫x1​dx=log⁡|x|+C.

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