_-1^1 0.05em 1+x+x^2- 1-x+x^2 1+x+x^2+ 1-x+x^2 dx is equal to

Question

Accepted Answer

Correct answer: C. (c) I= _-1^1 0.05em 1+x+x^2- 1-x+x^2 1+x+x^2+ 1-x+x^2 dx Let f (x )= 1+x+x^2- 1-x+x^2 1+x+x^2+ 1-x+x^2 Replacing x by -x, we get f (-x )= 1-x+x^2- 1+x+x^2 1-x+x^2+ 1+x+x^2= 1+x+x^2- 1-x+x^2 1+x+x^2+ 1-x+x^2=-f (x ) So, f (x ) is an odd function. ∴ 0.05emf (x ) dx=0

$\int_{- 1}^{1} \frac{1 + x + x ^{2} - 1 - x + x ^{2}}{1 + x + x ^{2} + 1 - x + x ^{2}} dx is equal to$

Solution

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