- A2π3
- B81π
- C2π
- Dπ
Solution
(d) Given, cos3xsinx+cos9xsin3x+cos27xsin9x+cos81xsin27x
Multiply and divide by 2 .
=21(cos3xcosx2sinxcosx+cos9xcos3x2sin3xcos3x+)cos27xcos9xsin9xcos9x
(+cos81xcos27x2sin27xcos27x)
=21(cos3xcosxsin2x+cos9xcos3xsin6x+cos27xcos9xsin18x)
(+cos81xcos28xsin54x)
i.e. 2x=3x−x
=21(cos3xcosxsin(3x−x)+cos9xcos3xsin(9x−3x)+cos27xcos9xsin(27x−9x))
(+cos81xcos27xsin(81x−27x))
=21[tan3x−tanx+tan9x−tan3x+tan27x
=21[tan(81x)−tanx]
∴Requiredperiodisπ.More Trigonometric Ratios & Identities PYQs
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