- A5cosθ
- B5sinθ
- C5sinθ
- D5cosθ
Solution
(d) cosθ−sinθ=5sin5
(cosθ−sinθ)2=(5sinθ)2
cos2θ+sin2θ−2sinθcosθ=5sin2θ
1−2sinθcosθ=5sin2θ
1−5sin2=2sinθcosθ
Now,(cosθ+4sinθ)2=cos2θ+16sin2θ+4.2sinθcosθ
=cos2θ+16sin2θ+(1−5sin2θ)
=cos2θ+16sin2θ+4−20sin2θ
=cos2θ−4sin2θ+4=cos2θ+4(1−sin2θ)
=cos2θ+4cos2θ=5cos2θ
∴cosθ+4sinθ=5cos2θ=5⋅cosθMore Trigonometric Ratios & Identities PYQs
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