An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity, $σ = 10 mho / m$ . The ratio of maximum conduction current density to maximum displacement current density is $____$ .
$(Take)$ $(\frac{1}{4 π ϵ _{o}} = 9 \times 10^{9} Nm^{2} / C^{2})$

Question

An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity,

σ = 10 mho / m

. The ratio of maximum conduction current density to maximum displacement current density is

____

.

(Take)

(\frac{1}{4 π ϵ _{o}} = 9 \times 10^{9} Nm^{2} / C^{2})

Accepted Answer

Correct answer: 1800. (1800) For an electromagnetic wave in a conducting medium, the maximum conduction current density is J_c , max= E_0 and maximum displacement current density is J_d , max=ϵ_0 E_0. The ratio is: J_c , maxJ_d , max= ϵ_0 . With =10 mho/m ,f=100 MHz So =2 10^8 rad/s, and ϵ_0= 10^-936 F/m : J_c , maxJ_d , max= 10 36 10^-9 2 10^8= 10 362 10^-1=1800.

$An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity, σ = 10 mho / m . The ratio of maximum conduction current density to maximum displacement current density is____. (Take) (\frac{1}{4 π ϵ _{o}} = 9 \times 10^{9} Nm^{2} / C^{2})$

Solution

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