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JEE · NEET Previous Year Question

$The ratio of average electric energy density and total average energy density of electromagnetic wave is:$

Topic: JEE PYQ

Answer: D. Full step-by-step solution below.

A $2$
B $1$
C $3$
D $\frac{1}{2}$

Correct answer: D

Solution

(d) < u_{E} >=< u_{B} >= \frac{1}{2} < u_{total} > So \frac{( u _{E} )}{( u _{total} )} = \frac{1}{2}

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