The oscillating magnetic field in a plane electromagnetic wave is given by B_y=5 10^-6 sin1000 (5x-4 10^8t)T. The amplitude of electric field will be:

Question

Accepted Answer

Correct answer: D. (d) B_0 = 5 x 10-6 v = Speed of wave = 4 10^85=8 10^7( ∴v= wk) E_0=vB_0=40 10^1 =4 10^2 V/m

$The oscillating magnetic field in a plane electromagnetic wave is given by B_{y} = 5 \times 1 0^{- 6} sin 1000 π (5 x - 4 \times 1 0^{8} t) T . The amplitude of electric field will be:$

Solution

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