JEE Previous Year Question

A cricket ball of mass $0.15\text{kg}$ is thrown vertically up by a bowling machine so that it rises to a maximum height of $20m$after leaving the machine. If the part pushing the ball applies a constant force $F$ on the ball and moves horizontally a distance of $0.2m$while launching the ball, the value of $F\text{(}$ in $N\text{)}$ is $g=10m{s}^{-2}$

Topic: JEE PYQ

Answer: 150. Full step-by-step solution below.