A body of mass 2 kg moves under a force of (2i+3j+5k )N. It starts from rest and was at the origininitially. After 4s its new coordinates are (8 ,b ,20 ). The value of b is. (Round off to the Nearest…

Question

A body of mass 2 kg moves under a force of (2i+3j+5k )N. It starts from rest and was at the origininitially. After 4s its new coordinates are (8 ,b ,20 ). The value of b is. (Round off to the Nearest Integer)

Accepted Answer

Correct answer: 12. (12) a= Fm= 2i+3j+5k2 =i+1.5j+2.5k =ut+ 12at^2 =0+ 12 (i+1.5j+2.5k ) (16 ) =8i+12j+20k b=12

$A body of mass 2 kg moves under a force of (2 i + 3 j + 5 k) N . It starts from rest and was at the origininitially. After 4 s its new coordinates are (8, b, 20) . The value of b is. (Round off to the Nearest Integer)$

Solution

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