Nickel (Z = 28) combines with a uninegative monodenate ligand to form a diamagnetic complex [NiL_4]^2–. The hybridisation involved and the number of unpaired electrons present in the complex are resp…

Question

Nickel (Z = 28) combines with a uninegative monodenate ligand to form a diamagnetic complex [NiL_4]^2–. The hybridisation involved and the number of unpaired electrons present in the complex are respectively:

Accepted Answer

Correct answer: B. (b) Monodentate ligand is uninegative and hence, the oxidation number of Ni in ( NiX_4 )^2- is +2 The electronic configuration of Ni^2+ is [ Ar ]3d^8. If the compound is diamagnetic it means all the electrons are paired. Hence, there will be one 3d orbital empty and one 4s orbital empty. The hybridisation involved in the formation of complex ( NiL_4 )^-2 is dsp^2.

$Nickel (Z = 28) combines with a uninegative monodenate ligand to form a diamagnetic complex [N i L_{4}]^{2-} . The hybridisation involved and the number of unpaired electrons present in the complex are respectively:$

Solution

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