CORRECT order of stability for the following is CH_2= CH^- , CH_3- CH_2^- , CH ≡C^-

Question

Accepted Answer

Correct answer: B. (b) Carbanion stability is determined by the s-character of the hybrid orbital bearing the negative charge. The acetylide anion CH ≡C^-has the carbanion on an sp hybridized carbon (50% s-character), providing optimal stabilization through efficient overlap with the charged orbital. The vinyl anion CH_2= CH^-has the carbanion on an sp^2 hybridized carbon (33% s-character), offering moderate stabilization. The primary alkyl anion CH_3- CH_2^-has the carbanion on an sp^3 hybridized carbon ( 25 \% s-character), providing the least stabilization. Greater s-character enables better penetration of the nucleus and enhanced stabilization of the negative charge. Therefore, the order is CH ≡C^-> CH_2= CH^-> CH_3- CH_2^-.

$CORRECT order of stability for the following is CH_{2} = CH^{-}, CH_{3} - CH_{2}^{-}, CH \equiv C^{-}$

Solution

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