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JEE · NEET Previous Year Question

$CH_{3} - CH = CH - CH_{2} OH \to PCC CH_{3} - CH = CH - CHO Hybridisation change involved at C - 1 in the above reaction is$

Topic: JEE PYQ

Answer: C. Full step-by-step solution below.

A $s p^{3} to sp$
B $s p^{2} to s p^{3}$
C $s p^{3} to s p^{2}$
D $sp to s p^{2}$

Correct answer: C

Solution

(b) : CH_{3} - CH = CH - CH s p^{3} H_{2} OH \to PCC s p^{2} CH_{3} - CH = CH - CHO Hybridisation at C - 1 is changed from s p^{3} to s p^{2}

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