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JEE · NEET Previous Year Question

$Temperature of 25^{\circ} C in Fahrenheit and Kelvin scale respectively are$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $77^{\circ} F and 298.15 K$
B $17^{\circ} F and 298.15 K$
C $45^{\circ} F and 260.15 K$
D $47^{\circ} F and 312.15 K$

Correct answer: A

Solution

(a) : oF = \frac{9}{5} (^{\circ} C) + 32 = (\frac{9}{5} \times 25) + 32 = 45 + 32 = 77 25^{\circ} C = (273.15 + 25) K = 298.15 K

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