100 mL of 0.1M acetic acid is completely neutralized using a standard solution of NaOH. The volume of ethane obtained at STP after the complete electrolysis of the resulting solution is

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Correct answer: A. (a): CH_3 COOH+ NaOH ⟶ CH_3 COONa 2 CH_3 COONa+2H_2O ⟶ CH_3- CH_3+2 CO_2+2 NaOH+H_2 Number of moles of acetic acid = Number of moles of sodium acetate =0.1 100=10 mmoles =10 10^-3 moles 2 moles of CH_3 COONa on electrolysis produces 22400 mL of ethane. ∴ 10 10^-3 moles of CH_3 COONa will produce = 22400 10 10^-32=112 mL of ethane .

$100 mL of 0.1 M acetic acid is completely neutralized using a standard solution of NaOH . The volume of ethane obtained at STP after the complete electrolysis of the resulting solution is$

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