The density of 2 M aqueous solution of NaOH is 1.28 g/ cm^3. The molality of the solution is [Given that molecular mass of NaOH=40 g mol^-1 ]

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Correct answer: C. (c) Density =1.28 g/ cc Conc. of solution =2M Molar mass of sodium hydroxide =40 g mol^-1 Volume of solution =1 L=100 mL Mass of Solution = d V =1.28 1000 =1280 g Mass of Solute = Number of Moles Molar Mass =2 40 = 80 g Mass of solvent = (1280-80 )g=1200 g Number of moles of solute = 8040=2 ∴ Molality = 2 10001200=1.67 molal

$The density of 2 M aqueous solution of NaOH is 1.28 g / cm^{3} . The molality of the solution is [Given that molecular mass of NaOH = 40 g mol^{- 1}]$

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