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JEE · NEET Previous Year Question

$The molarity of the solution containing 2.8% (mass / volume) solution of KOH is: (Given atomic mass of K = 39) is:$

Topic: JEE PYQ

Answer: B. Full step-by-step solution below.

A $0.1 M$
B $0.5 M$
C $0.2 M$
D $1 M$

Correct answer: B

Solution

(b) Weight of KOH = 2.8 gram Volume of solution = 100 ml M = \frac{2.8 \times 1000}{56 \times 100} = \frac{28}{56} = 0.5

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