For one mole of an ideal gas, increasing the temperature from 10^ C to 20^ C

Question

Accepted Answer

Correct answer: D. (d) : Initial temperature =283 K Final temperature =293 K KE_1= 3RT_12 ,KE_2= 3RT_22 KE_1KE_2= T_1T_2= 283293=0.96 KE_2=1.04KE_1 v_ rms= 3 RTM ; v_1v_2= T_1T_2 ⇒ 283293 v_2=v_1 293283=1.02v_1 Both average K.E. and rms velocity increase but not significantly.

$For one mole of an ideal gas, increasing the temperature from 10^{\circ} C to 20^{\circ} C$

Solution

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