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JEE · NEET Previous Year Question

$If the kinetic energy of O_{2} gas is 4.0 kJ mol^{- 1}, its RMS speed in cm s^{- 1} is$

Topic: JEE PYQ

Answer: C. Full step-by-step solution below.

A $5.0 \times 10^{2}$
B $5.0 \times 10^{3}$
C $5.0 \times 10^{4}$
D $5.0\times105$

Correct answer: C

Solution

(c) KE = \frac{3 RT}{2} and v_{rms} = \frac{3 RT}{M} v_{rms} = \frac{2 K}{M} \frac{E}{2} = \frac{2 \times 4 \times 10 ^{3} J}{32 \times 10 ^{- 3} kg mol ^{- 1}} = 5 \times 10^{2} m / s = 5 \times 10^{4} cm / s

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