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JEE · NEET Previous Year Question

$The volume of 2.8 g of CO at 27^{\circ} C and 0.821 atm pressure is (R = 0.08210 lit atm (K^{- 1} mol^{- 1})$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $3 litres$
B $30 litres$
C $0.3 litres$
D $1.5 litres$

Correct answer: A

Solution

(a) : n = \frac{2.8 g}{28 g mol ^{- 1}} = 0.1 mol From ideal gas equation, PV = nRT V = \frac{nRT}{P} = \frac{0.1 mol \times 0.08210 L atm mol ^{- 1} K ^{- 1} \times 300 K}{0.821 atm} = 3 L

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