A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of length L and height h. What is the speed of its centre of mass when the cylinder reaches its bottom?

Question

Accepted Answer

Correct answer: C. (c) Potential energy of the solid cylinder at height V= Mgh K.E. of centre of mass when reached at bottom = 12Mv^2+ 12I ^2= 12Mv^2+ 12Mk^2v^2/R^2 = 12Mv^2(1+ k^2R^2) For a solid cylinder k^2R^2= 12K .E .= 34Mv^2 Mgh= 34Mv^2 v= 43 gh .

$A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of length L and height h . What is the speed of its centre of mass when the cylinder reaches its bottom?$

Solution

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