A circular plate A of radius 1.5r is removed from one edge of a uniform circular plate B of radius 2 r. The distance of centre of mass of the remaining portion from the centre of the plate B is

Question

Accepted Answer

Correct answer: B. (b) Radius of removed circular plate, A=1.5r Radius of circular plate, B=2r Let mass of circular plate A ,M_1=M So surface mass density, = M (2r )^2= M4 r^2 Then mass of removed circular plate, A M_2= A= M4 r^2 (1.5r )^2= M4 1.5 1.5=0.5625M The distance of centre of mass of the remaining portion from the centre of the plate B is X_ cm= M_1x_1-M_2x_2M_1-M_2= M 0-0.5625M 0.5gM-0.5625M= 9r14

$A circular plate A of radius 1.5 r is removed from one edge of a uniform circular plate B of radius 2 r. The distance of centre of mass of the remaining portion from the centre of the plate B is$

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