A circular ring of mass 10 kg rolls along a horizontal floor. The centre of mass of the ring has a speed 1.5m/s. The work required to stop the ring is

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Accepted Answer

Correct answer: D. (d) According to work energy theorem, work required to stop the ring. W= change in kinetic energy = Kf- Ki=0-K_ rotational +K_ linear = 12I ^2+ 12mv^2= 12mR^2 ( vR )^2+ 12mv^2= 12mv^2+ 12mv^2=mv^2=10 (1.5 )^2=22.5J=-22.5J

$A circular ring of mass 10 kg rolls along a horizontal floor. The centre of mass of the ring has a speed 1.5 m / s . The work required to stop the ring is$

Solution

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