Two slits in Young's experiment have widths in the ratio 1 :25. The ratio of intensity at the maxima and minima in the interference pattern I_ maxI_ min is

Question

Accepted Answer

Correct answer: A. (a) Given, YDSE experiment, having two slits of width are in the ratio of 1 :25. So, ratio of intensity, I_1I_2= _1 _2= 125 ⇒ I_2I_1= 251 I_ maxI_ min= ( I_2+ I_1)^2( I_2- I_1)^2= ( I_2I_1+1 I_2I_1-1 )^2 ⇒ ( 5+15-1 )^2= ( 64 )^2= 3616= 94 Thus, I_ maxI_ min= 94

$Two slits in Young's experiment have widths in the ratio 1 : 25 . The ratio of intensity at the maxima and minima in the interference pattern \frac{I _{max}}{I _{min}} is$

Solution

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